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04-01-2011, 03:39 PM

.pptx   e- scattering.pptx (Size: 107.66 KB / Downloads: 91)


The conductivity σ may be obtained experimentally .
Further we can get ť by using eqn given below
σ = ( n*Qe2 *ť )/me ---------(1)
but ť obtained may not be accurate but we will get an idea of magnitude of ť . In a monovalent metal no of free e- /m3 is equals the no of atoms /m3 . From table we find that relaxation time T is of the order of 10-14 sec .Thus we can say that T is extremely small for monovalent metals.
from eqn. given below we can calculate mean free path λ-

λ = Vx * ťc ----------(2)

The relaxation time ť for metals refers to e- with Fermi velocity Vf .For usual values of temp. T , it may be shown that the scattering in these monovalent metals is isotropic . Then<cos θ>, ť=tc & λ = Vx * ťc .The values of man free path at 0 0c are several hundred angstroms.

We find from the graph shown that as we goes on reducing the temp of a metal then it’s resistivity also decreases & vice versa but assume a constant value of temp. below 6 K.
In general, the resistivity of a perfect, pure single crystal of a metal approaches to zero as temp. T approaches zero. This signifies that at very low temp. the mean free path λ assumes microscopic values .This concludes that the earlier discussions are not individual ion cores.

Thinking To Register

25-10-2012, 03:26 AM

why do we call it electron scattering, in fact i want to know more about it in an atom ??
please answer it for me
i will be grateful to uSmile
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25-10-2012, 10:47 AM

to get information about the topic "ELECTRON SCATTERING & RESISTIVITY OF METALS"full report refer the link bellow


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